HOW TO MAKE MOLAR SOLUTION OF AMMONIUM HYDROXIDE
Following things Required to make Molar Solution :
Molecular Formula
Molecular Weight
Assay or Purity of Compound
Weight per ml of compound (In case of Liquid)
Solvent as per your Requirement
If the compound in liquid form, We devide the required weight by weight per ml of that compound to conversion in milliliters
Formula:-
Mol.Weight of Compound(in gram) x Required Molarity(M) x Required Volume(ml) x 100
1000 x Assay or Purity of Compound
EXAMPLE: We want to make 500 ml solution of 0.1M Ammonium
Hydroxide
Following
things Required to make Molar Solution :
Molecular Formula : NH4OH
Molecular
Weight : 35.04
Purity
or Assay of Ammonium Hydroxide : 100.00% w/w
Theoretical
Purity or assay of Ammonia in Ammonium Hydroxide : 48.60% w/w
It
means 100gm of Ammonium Hydroxide contains 48.60 gm of Ammonia
Assay
or Purity of Strong Ammonia Solution :
25.0 % w/w
Weight
per ml of Strong Ammonia Solution: Approx 0.91
Please
put the values in following formula:-
Mol.Weight
of Compound(in gram) x Required Molarity(M) x Required Volume(ml) x 100
1000 x Assay or Purity of
Compound
= 35.04 (in gram) x 0.1(M) x 500 (ml) x
100
1000 x 100.00
= 1.752 gm of Ammonium Hydroxide Required
= 1.752
x 48.60 (Ammonia in Ammonium Hydroxide)
100
= 0.851472 g Ammonia Required
We take Strong Ammonia Solution for making the Solution
= 0.851472 x 100
25.00 (Assay or Purity of
Strong Ammonia Solution)
= 3.405888 gm of Strong Ammonia Solution
Required
= 3.405888 gm
0.91 (Wt.per ml of Strong
Ammonia Solution)
= 3.74 ml Strong Ammonia Solution Required to make 500ml
solution of 0.1M
Ammonium Hydroxide
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