How to make solution of millimoles. There are 1000 millimoles per mole: 1 mole = 1000 millimoles. Another way of expressing the relationship is 1 moles/ 1000 = 1 millimole. EXAMPLE For Ferric Oxide : you need to find the molecular weight for Ferric Oxide with the chemical formula of Fe 2 O 3 . Look up the atomic weight of iron and oxygen on the periodic table. The atomic weight of iron is 55.845 and the atomic weight of oxygen is 15.999. Add the weight of each atom in the compound: Molecular Weight of Fe 2 O 3 = 2 x 55.845 + 3 x 15.999 = 111.69 + 47.997 = 159.687 This is the weight in grams of 1 mole of the compound. Convert the weight of one mole to the weight of one millimole. Based in the metric system, one millimole is the same as one mole divided by 1,000. Therefore, the weight of one millimole is equal to the weight of one mole divided by 1,000. Continuing the example: 1 mole of Fe 2 O 3 = 159.687 grams per liter and 1 millimole of Fe 2 O 3 = 159.687...
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Difference Between μg ,mcg or ppm
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Difference Between μg ,mcg or ppm All are same, why we can say all are same Tri to understand as following μg = one millionth ( 1×10 −6 ) of a gram , = one gram/1000000 = 0.000001g or 0.001mg mcg = one millionth ( 1×10 −6 ) of a gram = one gram/1000000 = 0.000001g or 0.001mg ppm = ppm (parts-per-million) one millionth ( 1×10 −6 ) of a gram . =one gram/1000000 = 0.000001g. or 0.001mg So, we can say that the μg ,mcg or ppm are same. For example : We want to make 100ml of 10 μg/ml dilution. = 10 x 0.000001g( μg )= 0.00001g/ml or 0.01mg/ml. For 100ml = 0.01mg x 100ml or...
METHOD OF ANALYSIS OF TOLNAFTATE
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METHOD OF ANALYSIS OF TOLNAFTATE Weight accurately about 0.4 g of Tolnaftate, dissolve in 50 ml of anhydrous glacial acetic acid . Previously neutralized with 0.1 M Perchloric acid . Using Crystal Violet as indicator and add 20 ml mercuric acetate solution ( Previously neutralized with 0.1 M Perchloric acid . Using Crystal Violet as indicator) Titrate with 0.1 M Perchloric acid upto green colour changed. Each ml of 0.1 M Perchloric acid is equivalent to 0.030741g of Tolnaftate .
Analysis Method of Benzalkonium Chloride in Medicated Pad by UV Spectrophotometer
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Analysis Method of Benzalkonium Chloride in Medicated Pad by UV Spectrophotometer Each Medicated Pad Contain BENZALKONIUM CHLORIDE 0.5% w/w (As BENZALKONIUM CHLORIDE SOLUTION I.P.) Reagent :- 0.01 M Hydrochloric Acid Picric acid solution :- Weigh about 100 mg of Picric Acid and 14.5 g of Anhydrous Sodium acetate to a 500 ml volumetric Flask, and dissolve in 400 ml of Water.Add 20 ml Of glacial acetic acid,dilute with water to volume And mix. Test Solution :- Remove the medicated pad from the tape by the help Of forcep.and take about 80 mg of medicated pad in Stoppered test tube and add 20 ml of 0.01 M Hydrochloric acid and shake vigorously for 15 minutes Std. Praparation :-Weigh accurately about 200 mg of Benzalkonium Chloride solution (50% w/w) or according to sample Dissolve in 100 ml volumetric flask with 0.01 M Hydrochloric acid.take 2 ml of this solution and make Up 100 ml with 0.01 M Hydrochloric acid ...